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Q : 11.3 The photoelectric cut-off voltage in a certain experiment is . What is the maximum kinetic energy of photoelectrons emitted?
Answers (1)
Since the photoelectric cut-off voltage is 1.5 V. The maximum Kinetic Energy (eV) of photoelectrons emitted would be 1.5 eV.
KEmax=1.5 eV
KEmac=2.410-19 J
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