Q 9.15 (d) Use the mirror equation to deduce that:
an object placed between the pole and focus of a concave mirror produces a virtual and enlarged image.
The focal length of concave mirror is always negative.
Also conventionally object distance is always negative.
So we have mirror equation:
Now in this equation whenever , will always be positive which means is always positive which means it lies on the right side of the mirror which means image is always virtual.
Now,
since the denominator is always less than the numerator, so the magnitude magnification will always be greater than 1
Hence we conclude that image is always gonna be enlarged.
Hence an object placed between the pole and focus of a concave mirror produces a virtual and enlarged image.