7.52 What is the pH of 0.001M aniline solution? Calculate the degree of ionization of aniline in the solution. Also, calculate the ionization constant of the conjugate acid of aniline.(Kb = )
We have,
C = 0.001 M
=
Degree of ionization of aniline (a) = ?
Ionization constant of the conjugate acid () = ?
We know that
=
= (0.001)
Thus
=
Then [Base] = C.a = ()()
=
Now,
= 14 - 6.187
= 7.813
It is known that,
So,
This is ionization constant.