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When Cu^{2+} ion is treated with KI, a white precipitate is formed. Explain the reaction with the help of the chemical equation.

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Iodide ions reduce the Cu^{2+} ions :

\text {2Cu}^{2+}+\text {4I}^{-}\rightarrow \text {Cu}_{2}\text {I}_{2}\text {(White ppt.)}+\text {I}_{2}

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