Get Answers to all your Questions

header-bg qa

Which of the following lanthanoids show +2 oxidation state besides the characteristic oxidation state +3 of lanthanoids?

(i) \text {Ce}

(ii) \text {Eu}

(iii) \text {Yb}

(iv) \text {Ho}

Answers (1)

The answer is the option (ii, iii)

(a) Cerium (Z=57)

Electronic Configuration =[Xe]4f^{5}5d^{0}6s^{2}

Oxidation state of Ce=+3,+4

(b) Europium (Z=63)

Electronic configuration = =[Xe]4f^{7}5d^{0}6s^{2}

Oxidation state of Eu=+2,+3

(c) Ytterbium (Z=70)

Electronic Configuration =[Xe]4f^{14}5d^{0}6s^{2}

Oxidation state of Yb=+2,+3

(d) Holmium (Z=67)

Electronic Configuration =[Xe]4f^{11}5d^{0}6s^{2}

Oxidation state of Ho=+3

Posted by

infoexpert23

View full answer