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With the help of a labelled diagram show that there are four octahedral voids per unit cell in a cubic close packed structure.
 

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In ccp, one octahedral void is present at the centre of body surrounded by six atoms at the centre of respective face.
Where Nc=Number of atoms at corner 

 Nf=Number of atoms at face centre 

=Nc*contribution+Nf*contribution

=8\times 18+6\times 12=4

 Position of octahedral voids=Edge centre and body centre

 Number of octahedral voids per unit cell in cubic close packing=Ne\times \frac{1}{4}+Nb\times 1=12\times \frac{1}{4}+1\times 1=4

  Number of octahedral voids=4 

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