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Explain solution for RD Sharma maths class 12 chapter 31 Mean and Variance of a Random Variable exercise multiple choice questions question 1 maths textbook solution

Answers (1)

Answer:

              a=\frac{1}{81}

Hint:

              To solve this we add the probability of all the variable,\sum_{i=0}^{n} P\left(X_{i}\right)=1

Given:

             

X 0 1 2 3 4 5 6 7 8
P\left ( x \right ) a 3a 5a 7a 9a 11a 13a 15a 17a

            

Solution:

The sum of all probabilities is equal to 1,

    \sum_{i=0}^{n} P\left(X_{i}\right)=1

Hence,a + 3 a + 5 a + 7 a + 9 a + 11 a + 13 a + 15 a + 17 a =1

\therefore a=\frac{1}{81}

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