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  • Need Solution for R.D.Sharma Maths Class 12 Chapter 31 Mean and Variance of a Random Variable Exercise Very Short Answer type Question 5 Maths Textbook Solution.

Need Solution for R.D.Sharma Maths Class 12 Chapter 31 Mean and Variance of a Random Variable Exercise Very Short Answer type  Question 5 Maths Textbook Solution.

Answers (1)

Answer: - \frac{19}{8}

Hint: - You must know the rules for solving probability distribution problems.

Given:

\begin{array}{|c|c|c|c|} \hline X=x_{i} & 1 & 2 & 3 \\ \hline P\left(X=x_{i}\right) & \frac{1}{4} & \frac{1}{8} & \frac{5}{8} \\ \hline \end{array}

Solution:

\begin{aligned} &\text { Mean }=\sum_{i=1}^{3} p_{i} x_{i} \\ \end{aligned}

\begin{aligned} &=p_{1} x_{1}+p_{2} x_{2}+p_{3} x_{3} \\ \end{aligned}

\begin{aligned} &=\frac{1}{4} \times 1+\frac{1}{8} \times 2+\frac{5}{8} \times 3 \\ \end{aligned}

\begin{aligned} &=\frac{1}{4}+\frac{2}{8}+\frac{15}{8} \\ \end{aligned}

\begin{aligned} &=\frac{2+2+15}{8} \\ &=\frac{19}{8} \end{aligned}

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