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  • Need Solution for R.D.Sharma Maths Class 12 Chapter 31 Mean and Variance of a Random Variable Exercise Very Short Answer type Question 6 Maths Textbook Solution.

Need Solution for R.D.Sharma Maths Class 12 Chapter 31 Mean and Variance of a Random Variable Exercise Very Short Answer type Question 6  Maths Textbook Solution.

Answers (1)

Answer: - 0.3

Hint: - You must know the rules for finding or solving probability distribution function.

Given: -

\begin{array}{|c|c|c|c|c|} \hline X=x_{i} & 1 & 2 & 3 & 4 \\ \hline P\left(X=x_{i}\right) & c & 2 c & 3 c & 4 c \\ \hline \end{array}

Solution:We know that sum of probability in a probability distribution is always 1.

\sum_{i=1}^{n} p_{i}=1

\begin{aligned} &\therefore P(x=1)+P(x=2)+P(x=3)+P(x=4)=1 \\ \end{aligned}

\begin{aligned} &c+2 c+3 c+4 c=1 \\ \end{aligned}

\begin{aligned} &10 c=1 \\ \end{aligned}

\begin{aligned} &c=\frac{1}{10} \\ \end{aligned}

\begin{aligned} &P(x \leq 2)=P(x=1)+P(x=2) \\ \end{aligned}

\begin{aligned} &=\frac{1}{10}+2 \times \frac{1}{10} \\ \end{aligned}

\begin{aligned} &=\frac{1}{10}+\frac{2}{10} \\ &=\frac{3}{10} \\ &=0.3 \end{aligned}

 

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