Browse by Stream
QnA
Home
QnA
Go To Your Study Dashboard

Get Answers to all your Questions

header-bg qa
  • Home
  • School
  • Explain Solution R.D.Sharma Class 12 Chapter 28 The Plane Exercise 28.13 Question 16 Sub Question 2 Maths Textbook Solution.

Explain Solution R.D.Sharma Class 12 Chapter 28 The Plane  Exercise 28.13 Question 16 Sub Question 2 Maths Textbook Solution.

Answers (1)

2\left(4-\lambda^{2}\right)-0\left(2-\lambda^{2}\right)-2\left(\lambda^{2}-2\right)=0

8-2 \lambda^{2}-2 \lambda^{2}+4=0

\lambda^{2}+\lambda^{2}-6=0

Let \lambda^{2}=t then

(t+3)(t-2)=0

Put value of t

\left(\lambda^{2}+3\right)\left(\lambda^{2}-2\right)=0is neglected because direction cosine cannot be imaginary

\lambda^{2}=-3

Therefore, \lambda=\pm \sqrt{2}

Posted by

infoexpert21

View full answer

Crack CUET with india's "Best Teachers"

  • HD Video Lectures
  • Unlimited Mock Tests
  • Faculty Support
cuet_ads

Similar Questions

Trending Articles/News

anam-khan

Board Exam Time Table 2025 Live: UP Board exams from February 24; CBSE, BSEB date sheet soon
anam-khan

CBSE Date Sheet 2025 Live: Class 10, 12 board exam dates soon; syllabus, sample papers
anam-khan

Extra time in CBSE exams for students with type 1 diabetes: Kerala SHRC seeks report on plea

Latest Question