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Name: Explain Solution R.D.Sharma Class 12 Chapter 28 The Plane Exercise 28.13 Question 16 Sub Question 2 Maths Textbook Solution.
Uploaded: Tue, 2021-08-31 19:26
Description: Explain Solution R.D.Sharma Class 12 Chapter 28 The Plane Exercise 28.13 Question 16 Sub Question 2 Maths Textbook Solution.

#RD Sharma Vol. 2 Class 12
#CBSE 12 Class
#School
#Maths
#R.D. Sharma
#The Plane

#1.3
#10.1
#Fill in the blanks
#Very Short Answer type
#Multiple Choice Questions (MCQs)
#18.13
#28.1
#28.2
#28.3
#28.4
#28.5
#28.6
#28.7
#28.8
#28.9
#28.10
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Explain Solution R.D.Sharma Class 12 Chapter 28 The Plane Exercise 28.13 Question 16 Sub Question 2 Maths Textbook Solution.

Answers (1)

$2\left(4-\lambda^{2}\right)-0\left(2-\lambda^{2}\right)-2\left(\lambda^{2}-2\right)=0$

$8-2 \lambda^{2}-2 \lambda^{2}+4=0$

$\lambda^{2}+\lambda^{2}-6=0$

Let $\lambda^{2}=t$ then

$(t+3)(t-2)=0$

Put value of t

$\left(\lambda^{2}+3\right)\left(\lambda^{2}-2\right)=0$ is neglected because direction cosine cannot be imaginary

$\lambda^{2}=-3$

$Therefore, \lambda=\pm \sqrt{2}$

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Explain Solution R.D.Sharma Class 12 Chapter 28 The Plane Exercise 28.13 Question 16 Sub Question 2 Maths Textbook Solution.

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