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Explain Solution R.D. Sharma Class 12 Chapter 30 Probability  Exercise 30.4 Question 22 Sub Question 2 Maths Textbook Solution.

Answers (1)

Answer\frac{49}{121}

Hint: Probability=\frac{No\: of\: outcomes}{Total\: outcomes}

Given: An urn contains 4 red and 7 black balls. Two balls are drawn at random with replacement. Find the probability of getting 1) 2 black balls

Solution:

                Total\: \: balls = 4 red+7 black=11 balls

                \begin{aligned} P(2 \text { black balls }) &=P(\text { first is black }) \times P(\text { second is black }) \\ =& \frac{7}{11} \times \frac{7}{11} \ldots\{\text { as replacement is allowed }\} \\ \end{aligned}

                                               \begin{aligned} &=\frac{49}{121} \end{aligned}

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