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Need solution for RD Sharma Maths Class 12 Chapter 26 Directions Cosines and Direction Ratios Exercise Very Short Answer Question, question 5.

Answers (1)

Answer:

7, -2, 3

Hint:

Distance =\left|\frac{a x_{1}+b y_{1}+c z_{1}+d}{\sqrt{a^{2}+b^{2}+c^{2}}}\right|

Given:

P(7, -2, 3) from xy plane

Solution:

Distance of P(7, -2, 3) from xy-plane

i.e, z=0, a=0, b=0, c=1, d=0

Distance=\left|\frac{0 \times 7+0 \times-2+1 \times 3+0}{\sqrt{0^{2}+0^{2}+1^{2}}}\right|=3

Distance of P(7, -2, 3) from yz-plane

i.e, x=0, a=1, b=0, c=0, d=0

Distance=\left|\frac{1 \times 7+0 \times-2+0 \times 3}{\sqrt{1^{2}+0^{2}+0^{2}}}\right|=7

Distance of P(7, -2, 3) from y, xz plane is -2.

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