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Provide solution for RD Sharma maths class 12 chapter 31 Mean and Variance of a Random Variable exercise 31 point 1 question 1 sub question 2 maths textbook solution

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Answer: The given distribution of probability is not a probability distribution.

Hint: \sum P\left ( x=n \right )=1

Given:

X 0 1 2
P\left ( X \right )     0.6 0.4 0.2


Solution:

\begin{aligned} &P(x=0)+P(x=1)+P(x=2) \\ &=0.6+0.4+0.2 \\ &=1.2 \neq 1 \end{aligned}

So, the given distribution of probabilities is not a probability distribution.

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