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  • Provide solution RD Sharma maths class 12 chapter 12 Derivative as a Rate Measure exercise case study based question, question 3 sub question 5 maths textbook solution

Provide solution RD Sharma maths class 12 chapter 12 Derivative as a Rate Measure exercise case study based question, question 3 sub question 5 maths textbook solution

Answers (1)

Answer: 

\frac{15}{13}

Hint:

 Here we use basic concepts of Pythagoras

Given:

 x=5km

y=12km

So, B=13km

Solution:

\theta , Be the angle formed by mall, Aarushi and Mira.

\begin{aligned} &\tan \theta=\frac{y}{x} \\ &\Rightarrow \sec ^{2} \theta \frac{d \theta}{d t}=\frac{x \frac{d y}{d x}-y \frac{d x}{d t}}{x^{2}} \\ &\Rightarrow \frac{13^{2}}{5^{2}} \frac{d \theta}{d t}=\frac{5 \times 15+10 \times 12}{5^{2}} \\ &\begin{aligned} \Rightarrow \frac{d \theta}{d t} &=\frac{195}{165} \\ &=\frac{15}{13} \end{aligned} \end{aligned}

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