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  • In a ABC, it is given that AD is the internal bisector of <img alt="\angle A" src="https://entrancecorner.on

In a \triangleABC, it is given that AD is the internal bisector of \angle A. If AB = 10 cm, AC = 14 cm and BC = 6 cm, then CD =?

Option: 1

3 cm


Option: 2

2.5 cm


Option: 3

2 cm


Option: 4

3.5 cm


Answers (1)

best_answer

Using Angle Bisector

\frac{B D}{D C}=\frac{A B}{A C}

\\ \frac{6-x}{x}=\frac{10}{14} \\ \\\frac{6-x}{x} = \frac{5}{7}

\\5 x=7(6-x) \\ 5 x=42-7 x \\ 5 x+7 x=42

5 x+7 x =42 \Rightarrow x=3.5

x=3.5

Posted by

Pankaj Sanodiya

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