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  • A ball of mass 1 kg falls from a height of 5m above the free surface of the water. The relative density of the solid ball is <img alt="s = \frac{2}{3}" src="https://entrancecorner.oncodecogs.c

A ball of mass 1 kg falls from a height of 5m above the free surface of the water. The relative density of the solid ball is s = \frac{2}{3}. The ball travels a distance of 2m under water and becomes stationary. The work done by the resistive force of water is:

Option: 1

-50 J


Option: 2

-20 J


Option: 3

-40 J


Option: 4

-30 J


Answers (1)

best_answer

From the Work-Energy theorem,

work done by all the forces = change in kinetic energy

\therefore (work done by gravity for 7m) + (work done by upthrust for 2m) + (work done by resistive forces) = 0 as \Delta KE = 0.

1 * 10 * 7 \cos 0\degree + \frac{1}{2/3 * \rho _{w}} \rho _{w}g * 2 \cos 180\degree +work done by resistive forces = 0

\implies Work done by resistive forces = -40 J

Posted by

Rishabh

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