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  • A bar magnet is passing through a conducting loop of radius with velocity . The radius of th

A bar magnet is passing through a conducting loop of radius \mathrm{R} with velocity v. The radius of the bar magnet is such that it just passes through the loop. The induced e.m.f. in the loop can be represented by the approximate curve :
Option: 1
Option: 2
Option: 3
Option: 4

Answers (1)

best_answer

         
\rightarrow As the  Solenoid  approaches the loop, the current in the loop (side facing solenoid anticlockwise direction) opposes the increasing in magnetic field lines - e_{1}= \frac{-d\phi }{dt}\; \; \left [ \frac{d\phi }{dt}\Rightarrow positive\, here \right ]
\rightarrow when solenoid is inside the loop there is no charge in field lines through the loop hence the induced emf is zero
\rightarrow As the solenoid passes through the loop, field  line associate with loop decreases

This decreases in flux associated with loop is opposed by increasing the field lines by the loop.(current is in clockwise direction)
e_{2} = \frac{-d\phi }{dt}
\frac{d\phi }{dt}\Rightarrow Negative\, \left ( because\, of\, decrease\, in\, flux \right )
e_{2}\Rightarrow +ve
The correct option is (3)

Posted by

vishal kumar

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