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  • A box contains 20 defective items and 80 nondefective items. If two items are selected at random without replacement, what will be the probability that both items are defective?<div class='qna-

A box contains 20 defective items and 80 nondefective items. If two items are selected at random without replacement, what will be the probability that both items are defective?

Option: 1

\frac{1}{5}


Option: 2

\frac{1}{25}


Option: 3

\frac{20}{99}


Option: 4

\frac{19}{495}


Answers (1)

best_answer

Given box 

  20 defective 
80non-defective

Probability that both the items are defective

=\left(\frac{20}{100}\right) \cdot\left(\frac{19}{99}\right)=\frac{19}{495}.
 

 

Posted by

Ritika Kankaria

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