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  • A chemical reaction takes place at constant pressure. The reaction releases of heat a

A chemical reaction takes place at constant pressure. The reaction releases 1500 \mathrm{~J} of heat and does 500 \mathrm{~J} of work on the surroundings. Determine the change in internal energy \mathrm{(\Delta U)} of the system.

Option: 1

1000 \mathrm{~J}


 


Option: 2

2000 \mathrm{~J}
 


Option: 3

3000 \mathrm{~J}
 


Option: 4

3400 \mathrm{~J}


Answers (1)

best_answer

Given data:

Heat released \mathrm{(Q)=1500 \mathrm{~J}}

Work done \mathrm{(W)=500 \mathrm{~J}}

The change in internal energy \mathrm{(\Delta U)} of the system can be calculated using the first law of thermodynamics:

\mathrm{ \Delta U=Q-W }

Substitute the given values and calculate \mathrm{ \Delta U: }

\mathrm{ \Delta U=1500 \mathrm{~J}-500 \mathrm{~J}=1000 \mathrm{~J} }

Therefore, the change in internal energy \mathrm{ (\Delta U) } of the system is \mathrm{ 1000 \mathrm{~J}. }

So, correct option is 1.

Posted by

Kuldeep Maurya

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