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A circular coil of radius 5 cm consists of exactly 250 turns. A magnetic field is directed perpendicular to its plane (as shown in Fig. 8) is increasing at a rate of 0.6 T/s. If the resistance of the coil is 8\Omega, find the current induced in the coil.

An increasing magnetic field B perpendicular to the loop induces current in the clockwise '

Option: 1

0.05 A


Option: 2

0.10 A


Option: 3

0.15 A


Option: 4

0.20 A


Answers (1)

best_answer

\mathrm{|\boldsymbol{E}|=N \frac{d \Phi_B}{d t}=N \pi R^2 \frac{d B}{d t} }

\mathrm{Here, \quad N=250 ; \quad R=5 \mathrm{~cm}=5 \times 10^{-2} \mathrm{~m}}

Therefore \mathrm{\frac{d B}{d t}=+0.6 \mathrm{~T} / \mathrm{s}}

\mathrm{\boldsymbol{E}=(250) \pi\left(5 \times 10^{-2}\right)^2(0.6)=1.18 \mathrm{~V}}

The magnitude of current is

\mathrm{I=\frac{E}{R}=\frac{1.18}{8}=0.15 \mathrm{~A}}

Posted by

Irshad Anwar

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