Browse by Stream
QnA
Home
QnA
Go To Your Study Dashboard

Get Answers to all your Questions

header-bg qa
  • Home
  • Engineering
  • A complex circuit consists of resistors R1, R2, and R3 connected in series to a constant voltage source of 24V. The currents flowing through each resistor are measu

A complex circuit consists of resistors R1, R2, and R3 connected in series to a constant voltage source of 24V. The currents flowing through each resistor are measured and recorded:

Resistor Current (A)
R1 0.5
R2 0.8
R3 1.2

Using this data, calculate the equivalent resistance of the entire circuit.

 

Option: 1

8.5 \Omega


Option: 2

98.5 \Omega


Option: 3

59.5 \Omega


Option: 4

7.5 \Omega


Answers (1)

best_answer

In a series circuit, the total resistance (Req) is the sum of the individual resistances:

                Req = R1 + R2 + R3

Let’s use the provided data points to calculate the equivalent resistance:

Resistor Current (A)
R1 0.5
R2 0.8
R3 1.2

We’ll use Ohm’s law to find the resistance of each resistor:

                R = \frac{V}{I}

where V is the constant voltage (24V) and I is the current.

                R_{1} = \frac{24}{0.5} = 48 \Omega

                R_{2} = \frac{24}{0.8} = 30 \Omega

                R_{3} = \frac{24}{1.2} = 20 \Omega

Now, calculate the equivalent resistance:

       Req = R1 + R2 + R3 = 48 + 30 + 20 = 98 \Omega

Hence, the equivalent resistance of the entire circuit is 98 \Omega.

Posted by

chirag

View full answer

JEE Main high-scoring chapters and topics

Study 40% syllabus and score up to 100% marks in JEE

Similar Questions

Trending Articles/News

anam-khan

JEE Main 2026: Wider gap in NIT cut-offs for home and other-state quotas; outsiders need better rank
anam-khan

JEE Mains 2026: Use of calculator 'not allowed’ says NTA; cites ‘typographical error' in information bulletin
anam-khan

JEE Main 2026: NIT Warangal attracts best talent with high BTech cut-offs in top, emerging branches

Latest Question