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  • A long, straight wire of radius 'a' carries a current distributed uniformly over its cross-section. The ratio of the magnetic fields due to the wire at distance 

A long, straight wire of radius 'a' carries a current distributed uniformly over its cross-section. The ratio of the magnetic fields due to the wire at distance \frac{a}{3} and 2a, respectively from the axis of the wire is:
Option: 1 \frac{3}{2}
Option: 2 2
Option: 3 \frac{2}{3}
Option: 4 \frac{1}{2}

Answers (1)

best_answer

 

 

 

 

B_A = \frac{\mu_0ir}{2\pi a^2} = \frac{\mu_0 i a}{\pi a^2 6} = \frac{\mu_0i}{6\pi a}

B_B = \frac{\mu_0i}{2\pi (2a)}

\frac{B_A}{B_B} = \frac{4}{6} = \frac{2}{3}

Hence the option correct option is (3).

Posted by

avinash.dongre

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