Go To Your Study Dashboard

Get Answers to all your Questions

header-bg

#Engineering

A mass of 10 kg is suspended by a rope of length 4m, from the ceiling. A force F is applied horizontally at the mid-point of the rope such that the top half of the rope makes an angle of $45^{\circ}$ with the vertical. Then F (in newtons) equals: (Take $\mathrm{g}=10 \mathrm{ms}^{-2}$ and the rope to be massless):
Option: 1 100
Option: 2 75
Option: 3 70
Option: 4 10

Answers (0)

Similar Questions

50 mL of 0.2 M ammonia solution is treated with 25 mL of 0.2 M HCl. If pKb of ammonia solution is 4.75, the pH of the mixture will be : Option: 1 3.75 Option: 2 4.75

Latest Question