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A metal (A) on heating in nitrogen gas gives compound B. B on treatment with H_{2}O gives a colourless gas which when passed through CuSO_{4} solution gives a dark blue-violet coloured solution. A and B respectively, are :
Option: 1 Na and Na_{3}N
Option: 2 Mg and Mg_{3}N_{2}
Option: 3 Mg and Mg(NO_{3})_{2}
Option: 4 Na and NaNO_{3}
 

Answers (1)

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Magnesium reacts with air to form its nitride. The nitride upon hydrolysis yields ammonia which gives a deep blue color solution with CuSO_4

3Mg+N_{2}\rightarrow \underset{(B)}{Mg_{3}N_{2}}\overset{H_{2}O}{\rightarrow}Mg(OH)_{2}+NH_{3}
CuSO_4 + 2NH_3 \longrightarrow [Cu(NH_3)_2]SO_4
 
Therefore, Option(2) is correct.

 

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vishal kumar

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