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  • A monochromatic neon lamp with wavelength of illuminates a photo-sensitive material which has a stopping voltage of <img alt="0.48 \mathrm{~V

A monochromatic neon lamp with wavelength of 670.5 \mathrm{~nm} illuminates a photo-sensitive material which has a stopping voltage of 0.48 \mathrm{~V}. What will be the stopping voltage if the source light is changed with another source of wavelength of 474.6 \mathrm{~nm} ?
Option: 1 1.5V
Option: 2 0.96\: V
Option: 3 0.24\: V
Option: 4 1.25\: V

Answers (1)

best_answer

\lambda _{1}= 6705 nm\\

(V_{0})_{1}= 0.48 V\\

\lambda _{2}= 474.6nm\\

By Einstein's photoelectric equation

\frac{hc}{\lambda _{1}}= \phi _{0}+e(V_{0})_{1}\\                   .................(1)

\frac{hc}{\lambda _{2}}= \phi _{0}+e(V_{0})_{2}\\                   .................(2)

\frac{hc}{\lambda _{1}}-\frac{hc}{\lambda _{2}}= e(V_{0})_{1}- e(V_{0})_{2}\\

\frac{1240}{670.5}(eV)-\frac{1240}{474.6}(eV)= 0.48eV-e(V_{0})_{2}\\

1.8493(eV)-2.613eV= 0.48eV-e(V_{0})_{2}\\

-0.7691-0.48= -(V_{0})_{2}\\

(V_{0})_{2}= 1.2491V

Posted by

vishal kumar

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