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A particular hydrogen-like ion emits radiation of frequency 2. 92\times 10^{15}Hz when it makes the transition from n = 3 to n = 1, The frequency in Hz of radiation emitted in transition from n =2 to n= 1 will be :
 
Option: 1 6\cdot 57\times 10^{15}
Option: 2 2\cdot 46\times10^{15}
Option: 3 0\cdot 44\times10^{15}
Option: 4 4\cdot 38\times10^{15}

Answers (1)

best_answer

f= 2\cdot 92\times 10^{15}Hz
\Delta E= hf= Rchz^{2}\left [ \frac{1}{n_f^{2}}-\frac{1}{n_i^{2}} \right ]
hf_{1}= Rchz^{2}\left [ \frac{1}{1^{2}}-\frac{1}{3^{2}} \right ]
hf_{2}= Rchz^{2}\left [ \frac{1}{1^{2}}-\frac{1}{2^{2}} \right ]
\frac{f_{1}}{f_{2}}= \frac{\frac{8}{9}}{\frac{3}{4}}= \frac{32}{27}
{f_{2}}= \left ( \frac{27}{32} \right )\times 2\cdot 92\times 10^{15}
{f_{2}}=2\cdot 46\times 10^{15}
The correct option is (2)

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vishal kumar

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