Browse by Stream
QnA
Home
QnA
Go To Your Study Dashboard

Get Answers to all your Questions

header-bg qa
  • Home
  • Engineering
  • A small square loop of wire of side   is placed inside a large square loop of wire <img alt="\mathrm{L}(\mathrm{L} \gg>l)" src="

A small square loop of wire of side \mathrm{}l  is placed inside a large square loop of wire \mathrm{L}(\mathrm{L} \gg>l). Both loops are coplanar and their centres coincide at point \mathrm{O} as shown in figure. The mutual inductance of the system is :

Option: 1

\begin{aligned} &\frac{2 \sqrt{2} \mu_{0} \mathrm{~L}^{2}}{\pi l} \\ \end{aligned}


Option: 2

\frac{\mu_{0} l^{2}}{2 \sqrt{2} \pi \mathrm{L}} \\


Option: 3

\frac{2 \sqrt{2} \mu_{0} l^{2}}{\pi \mathrm{L}} \\


Option: 4

\frac{\mu_{0} \mathrm{~L}^{2}}{2 \sqrt{2} \pi l}


Answers (1)

best_answer

                   

If current I is flowing through loop of of length L then the flux associated with the smaller loop is \mathrm{\Phi =Mi=(4B)A}

\mathrm{\left.M i=4[\frac{ \mu_0 i}{4 \pi(L / 2)}\left(\sin 45^{\circ}+\sin 45^{\circ}\right)\right] l^2 }

\mathrm{M=\frac{\mu_0 l^2}{\pi\L}(2 \sqrt{2})}

Hence (3) is correct option.

Posted by

manish

View full answer

JEE Main high-scoring chapters and topics

Study 40% syllabus and score up to 100% marks in JEE

Similar Questions

Trending Articles/News

anam-khan

Worried about IIT, NIT admission chances? JEE Main shift-wise marks vs percentile for session 1
anam-khan

Can I get NIT Bhopal with 95 percentile in JEE Mains 2025? BTech cut-offs
anam-khan

JEE Mains 2025 LIVE: NTA JEE session 1 results on February 12; April session registration ongoing, cut-offs

Latest Question