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A straight line conductor of length 0.4 m is moved with a speed of \mathrm{7 m/s } perpendicular to a magnetic field of intensity \mathrm{0.9\, wb/m^{2} }. The induced e.m.f. across the conductor is

Option: 1

\mathrm{5.04 V }


Option: 2

\mathrm{1.26 V}


Option: 3

\mathrm{2.52 V }


Option: 4

\mathrm{25.2 V }


Answers (1)

best_answer

Induced e.mf. \mathrm{=\mathrm{B\, l\, v} }
\mathrm{\therefore \quad \mathrm{e}=(0.9)(0.4)(7)=2.52 }

Posted by

Devendra Khairwa

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