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  • A straight line through origin O meets the lines 3y = 10 − 4x  and 8x + 6y + 5 = 0 at points A and B respectively.  Then O divides the segment AB in the ratio<div class='qna-opt

A straight line through origin O meets the lines 3y = 10 − 4x  and 8x + 6y + 5 = 0 at points A and B respectively.  Then O divides the segment AB in the ratio

Option: 1

 2 : 3


Option: 2

 1 : 2


Option: 3

4 : 1


Option: 4

 3 : 4

 


Answers (1)

best_answer

Given equation of the lien are

4x + 3y = 10

and 8x + 6y + 5 = 0

these lines are parallel to each other

Length of perpendicular from (0,0) to the line 4x + 3y = 10

p_1=\frac{|4\times 0+3\times 0-10|}{\sqrt{4^2+3^2}}=2 

Length of perpendicular from (0,0) to the line 8x + 6y = 5

p_2=\frac{|8\times 0+6\times 0-5|}{\sqrt{8^2+6^2}}=\frac{1}{2}

\therefore p_1:p_2=2:\frac{1}{2}=4:1

Posted by

Ritika Jonwal

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