#### $N_{2} + 3H_{2}\rightarrow2NH_{3}$After completion of 75% of the reaction what would be the mole fraction for the constituents ?Option: 1 0.1, 0,3, 0.6Option: 2 0.3, 0.1, 0.6Option: 3 0.6, 0.1, 0.3Option: 4 0.1, 0.6, 0.3

As we learnt in

Mole Fraction -

It is the ratio of moles of solute or moles of solvent to moles of solution.

If a substance ‘A’ dissolves in substance ‘B’ and their number of moles are $n_{A}$ and $n_{B}$ respectively; then the mole fractions of A and B are given as

75% of the reaction of 100% = 75/100 = 3/4

75% means 3/4 of the total time

t = 3/4

At   $t = \frac{3}{4}$?,

$N_{2} + 3H_{2}\rightarrow2NH_{3}$?

t=0                      1(Mole)    3                 0

t=3/4                 1 -3/4   3-(3* 3/4)     0+2*3/4

$t = \frac{3}{4}$?               $\frac{1}{4}$?            $\frac{3}{4}$?                $\frac{3}{2}$?

After t=3/4 Mole of substance will be-

Moles of N2 = 0.25

Moles of H2 = 0.75

Moles of NH3 = 1.5

Mole fraction of A = (number of moles of A)/(number of moles of solution ) = $n_{A}$?/($n_{A}$?+ $n_{B}$?)

Number of moles of solution = 0.25+ 0.75 + 1.5 = 2.5

Mole fraction of  $N_{2}=\frac{0.25}{2.5} =0.1$?

Mole fraction of  $H_{2}=\frac{0.75}{2.5} =0.3$?

Mole fraction of  $NH_{3}=\frac{1.5}{2.5} =0.6$?