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N_{2} + 3H_{2}\rightarrow2NH_{3}

After completion of 75% of the reaction what would be the mole fraction for the constituents ?

Option: 1

0.1, 0,3, 0.6


Option: 2

0.3, 0.1, 0.6


Option: 3

0.6, 0.1, 0.3


Option: 4

0.1, 0.6, 0.3


Answers (1)

best_answer

As we learnt in

Mole Fraction -

It is the ratio of moles of solute or moles of solvent to moles of solution.

If a substance ‘A’ dissolves in substance ‘B’ and their number of moles are n_{A} and n_{B} respectively; then the mole fractions of A and B are given as

 

75% of the reaction of 100% = 75/100 = 3/4

75% means 3/4 of the total time 

t = 3/4

 

 At   t = \frac{3}{4}?,

                         N_{2} + 3H_{2}\rightarrow2NH_{3}?

t=0                      1(Mole)    3                 0

t=3/4                 1 -3/4   3-(3* 3/4)     0+2*3/4

t = \frac{3}{4}?               \frac{1}{4}?            \frac{3}{4}?                \frac{3}{2}?

After t=3/4 Mole of substance will be-

Moles of N2 = 0.25

Moles of H2 = 0.75

Moles of NH3 = 1.5

Mole fraction of A = (number of moles of A)/(number of moles of solution ) = n_{A}?/(n_{A}?+ n_{B}?)

Number of moles of solution = 0.25+ 0.75 + 1.5 = 2.5

Mole fraction of  N_{2}=\frac{0.25}{2.5} =0.1?

Mole fraction of  H_{2}=\frac{0.75}{2.5} =0.3?

Mole fraction of  NH_{3}=\frac{1.5}{2.5} =0.6?

Posted by

sudhir.kumar

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