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An electric circuit is shown in figure the cells are of negligible internal resistances. The currents in 3\Omega resistance is:

Option: 1

0.17A


Option: 2

0.25A


Option: 3

0.13A


Option: 4

0.24A


Answers (1)

best_answer

Applying Kirchoff's Ist law at junction C, i=i_{1}+i_{_{2}}

Applying kirchoff's 2nd law to mesh ABCHA we have

4 = (3 + 5)i_{1} + 5i_{2}

= 8 i_{1} + 5i_{2} . . . (1)

Applying Kirchoff's 2nd law to mesh ABDCA, we have

4 + 8 = (10 + 6) i_{1}+ 5i_{2} + 5i_{1}

12 = 21 i_{2} + 5i_{1} . . . . (2)

from (1) and (2) i_{1} = 0.168 amp.

 

Posted by

himanshu.meshram

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