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An electromagnetic radiation has an energy of 13.2 \mathrm{keV} Then the radiation belongs to the region of

Option: 1

Visible light


Option: 2

Ultraviolet


Option: 3

Infrared


Option: 4

X-ray


Answers (1)

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Energy of a photon \mathrm{E=\frac{h c}{\lambda} }
\mathrm{\begin{aligned} & \therefore \quad \text { Wavelength } \lambda=\frac{h c}{E} \\ & =\frac{6.6 \times 10^{-34} \times 3 \times 10^8}{13.2 \times 10^3 \times 1.6 \times 10^{-19}} \\ & =0.9375 \times 10^{-10} \mathrm{~m} \\ & =1 \AA \end{aligned} }
Wavelength range of \mathrm{\mathrm{X}-rays\, \, is\, \, from 10^{-11} \mathrm{~m} to 10^{-8} m (0.1 \AA \, to \, 100 \AA). }
Therefore, the given electromagnetic radiation belongs to the X-ray region of electromagnetic spectrum.

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Shailly goel

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