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  • An experiment is conducted to measure the diameter of a thin wire using a screw gauge. The main scale reading is <img alt="M=3.0\ mm" src="https://entrancecorner.oncodecogs.com/gif.latex?M%3D3.0%5C

An experiment is conducted to measure the diameter of a thin wire using a screw gauge. The main scale reading is M=3.0\ mm, and the circular scale reading is C=35. The screw gauge has 50 divisions on its circular scale, and the least count is 0.01\ mm. Determine the diameter of the thin wire.

Option: 1

3.35\ mm


Option: 2

3.35\ cm


Option: 3

3.35\ m


Option: 4

33.5\ mm


Answers (1)

best_answer

Given values:

  • Main scale reading (M)=3.00\ mm
  • Circular scale reading (C)=35
  • Number of circular scale divisions (N)=50
  • Least count of the screw gauge =0.01\ mm

The total reading on the screw gauge can be calculated by adding the main
scale reading and the circular scale reading:
Total reading =M+C
Step 1: Calculate the total reading on the screw gauge:
Total reading = 3.0\ mm + 0.35\ mm = 3.35 \ mm

The least count of the screw gauge is 0.01\ mm, which means that one division
on the circular scale corresponds to 0.01\ mm.
Step 2: Calculate the actual reading by adding the number of circular scale
divisions that coincide with the main scale reading to the total reading:
Actual reading = Main \ scale\ reading + N \times{ Least \ count}
Actual reading = 3 \ mm + 35 \times 0.01\ mm

Diameter of rod = 3.35 \ mm
So, correct option is A

Posted by

sudhir.kumar

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