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An organic compound "A" on treatment with benzene sulphonyl chloride gives compound B. B is soluble in dil. NaOH solution. Compound A is:
Option: 1 \mathrm{C}_{6} \mathrm{H}_{5}-\mathrm{CH}_{2} \mathrm{NHCH}_{3}
Option: 2
Option: 3 \mathrm{C}_{6} \mathrm{H}_{5}-\mathrm{N}-\left(\mathrm{CH}_{3}\right)_{2}
Option: 4 \mathrm{C}_{6} \mathrm{H}_{5}-\mathrm{NHCH}_{2} \mathrm{CH}_{3}

Answers (1)

best_answer

Hinsberg reagent (Benzene sulphonyl chloride) gives a reaction and form an acidic product with 1° amine and it is soluble in dil. NaOH.

Therefore, the Correct option is (2)

Posted by

Kuldeep Maurya

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