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  • As per the given figure, a small ball P slides down the quadrant of a circle and hits the other ball Q of equal mass which is initially at rest. Neglecting the effect of friction and assume the col

As per the given figure, a small ball P slides down the quadrant of a circle and hits the other ball Q of equal mass which is initially at rest. Neglecting the effect of friction and assume the collision to be elastic, the velocity of ball Q after collision will be :

Option: 1

0 m/s


Option: 2

4 m/s 


Option: 3

2 m/s 


Option: 4

0.25 m/s


Answers (1)

best_answer

Energy conservation for ‘P’

\begin{aligned} & \mathrm{mgh}=\frac{1}{2} \mathrm{mV}^2 \\ & \mathrm{~V}=\sqrt{2 \mathrm{gh}} \\ & \mathrm{V}=\sqrt{2 \times 10 \times 0.2} \\ & \mathrm{~V}=2 \mathrm{~m} / \mathrm{sec} \end{aligned}

Now collision between P and Q is elastic and both have same mass then P will transfer all velocity to then Q. So velocity Q will be 2 m/sec

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Riya

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