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  • As shown in the figure, P and Q are two coaxial conducting loops separated by some distance. When the switch S is closed, a clockwise current IP flows in P (as seen by E) and an induced curr

As shown in the figure, P and Q are two coaxial conducting loops separated by some distance. When the switch S is closed, a
clockwise current IP flows in P (as seen by E) and an induced current 1 \; Q_{1} flow in Q. The switch remains closed for a long
time. When S is opened, a current 2\; Q_{1} flows in Q. Then the directions of I\; Q_{1}and I\; Q_{2} (as seen by E) are:

 

Option: 1

respectively clockwise and anti-clockwise
 


Option: 2

both clockwise
 


Option: 3

both anti-clockwise
 


Option: 4

respectively anti-clockwise and clockwise


Answers (1)

best_answer

In the first case, the current in loop P is increasing, hence current in loop Q is opposite to that in P and vice-versa.

Posted by

Rakesh

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