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As shown in the figure, P and Q are two coaxial conduction loops separated by some distance. When the switch S is closed, a clockwise current $I_P$ flows in P (as seen by E) and an induced current $I_{Q_1}$ flows in Q. The switch remains closed for a long time. When S is opened, a current $I_{Q_2}$ flows in Q. Then the direction $I_{Q_1}$ and $I_{Q_2}$ (as seen by E) are :

Option: 1
respectively clockwise and anticlockwise

Option: 2
both clockwise

Option: 3
both anticlockwise

Option: 4
respectively anticlockwise and clockwise

Answers (1)

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When switch S is closed magnetic field lines passing through Q increases in the direction from right to left. So, according to Lenz’s law induced current in Q i.e., $I_{Q_1}$ will flow in such a direction, so that the magnetic field lines due to $I_{Q_2}$ passes from left to right through Q. This is possible when $I_{Q_1}$ flows in anticlockwise direction as seen by E. Opposite is the case when switch S is opened i.e., $I_{Q_2}$ will be clockwise as seen by E

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