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As shown in the figure, P and Q are two coaxial conduction loops separated by some distance. When the switch S is closed, a clockwise current  I_P flows in P (as seen by E) and an induced current I_{Q_1} flows in Q. The switch remains closed for a long time. When S is opened, a current I_{Q_2} flows in Q. Then the direction I_{Q_1} and I_{Q_2} (as seen by E) are :
                         

Option: 1

respectively clockwise and anticlockwise


Option: 2

both clockwise 


Option: 3

 both anticlockwise 


Option: 4

respectively anticlockwise and clockwise 


Answers (1)

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When switch S is closed magnetic field lines passing through Q increases in the direction from right to left. So, according to Lenz’s law induced current in Q i.e.,I_{Q_1} will flow in such a direction, so that the magnetic field lines due to I_{Q_2} passes from left to right through Q. This is possible when I_{Q_1} flows in anticlockwise direction as seen by E. Opposite is the case when switch S is opened i.e., I_{Q_2} will be clockwise as seen by E

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