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At certain temperature, the half-life period in the thermal decomposition of a gaseous substance as follows:


\mathrm{C\left(\mathrm{~mol} \mathrm{~L}^{-1}\right) 2.6 \times 10^{-3} 5.2 \times 10^{-3} \\ }

\mathrm{t_{1 / 2}(\text { in min. }) 22 ~~~~~~~~~~~~~22 }

Find the order of reaction [Given: log (23.5) = 1.37; log (95) = 1.97]

 

Option: 1

0


Option: 2

1


Option: 3

2


Option: 4

3


Answers (1)

best_answer

\mathrm{t_{1 / 2} \propto \frac{1}{a^{(n-1)}} }

On increasing concentration by 2 times, the half-time remained unaffected. 

\mathrm{ \Rightarrow \mathrm{n}-1=0 \\ }

\mathrm{ \Rightarrow \mathrm{n}=1 }.

Posted by

avinash.dongre

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