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Calculate the value of mean free path (\lambda) for oxygen molecules at temperature 27^{\circ}C and pressure 1.01 \times 10^5 Pa. Assume the molecular diameter 0.3nm and the gas is ideal. (k =1.38 \times 10^{-23} JK^{-1})
Option: 1 102 nm
Option: 2 86 nm
Option: 3 58 nm
Option: 4 32 nm

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\begin{aligned} \lambda &=\frac{\mathrm{RT}}{\sqrt{2} \pi \mathrm{d}^{2} \mathrm{~N}_{\mathrm{A}} \mathrm{P}} \\ \lambda &=102 \mathrm{~nm} \end{aligned}

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