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Consider a long steel bar under a tensile force F acting at the edges along the length of the bar. Consider a plane making an angle $\Theta$ with the length. For what angle is the tensile stress is maximum ?

Option: 1
30°

Option: 2
45°

Option: 3
60°

Option: 4
90°

Answers (1)

best_answer

If A is the area of cross-section of the bar,then

$f=\frac{Fsin\Theta }{(\frac{A}{sin\Theta })}=\frac{F}{A}sin^{2}\Theta$

f will be maximum for $\Theta$ =90°

Posted by

shivangi.bhatnagar

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