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During confirmatory test of S^{2-} ion, purple colour appears due to presence of:

Option: 1

Na_2[Fe(CN)_5NO]


Option: 2

Na_4[Fe(CN)_5NOS]


Option: 3

K_2[Fe(CN)_5NO]


Option: 4

Na_4[Fe(CN)_6]


Answers (1)

As we learnt

 

Test of Sulfide ion -

 

Add a Sodium nitroprusside solution in an alkaline midium

Na_2S + Na_2(Fe(CN)_5NO) \overset{NaOH}{\rightarrow} Na_4(Fe(CN)_6 NOS) \: Purple

- wherein

Purple color confirm the presence of  S^{2-}

 

 Purple color is due to the formation of 

Na_4(Fe(CN)_6 NOS)

Posted by

Kshitij

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