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  • Element forms ccp structure and occupies half of the octahedral voids, while oxygen atoms occupy all the

Element 'B' forms ccp structure and 'A' occupies half of the octahedral voids, while oxygen atoms occupy all the tetrahedral voids. The structure of bimetallic oxide is :
 
Option: 1 A_{4}B_{2}O
Option: 2 AB_{2}O_{4}
Option: 3 A_{2}BO_{4}
Option: 4 A_{2}B_{2}O
 

Answers (1)

best_answer

 

 

Voids -

Voids are empty spaces in a unit cell. They are of four types: triangular, tetrahedral, octahedral, cubic.

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B forms ccp structure (FCC)

Number of atoms per unit cell of 'B'=\frac{1}{8}\times8+6\times\frac{1}{2}=4

'A' occupies half of the octahedral voids.

Number of atoms of element A:-\; \; \frac{1}{2}\left [ 12\times\frac{1}{4}+1 \right ]

                                                        =\frac{1}{2}\times4=2

'O' atoms occupy all the tetrahedral voids.

Number of atoms of \\O:-\; \; 8

[2 Td voids on 4 Body diagonal]

Structure of bimetallic oxide is :-

A_{2}B_{4}O_{8}=AB_{4}O_{4}

Posted by

Ritika Jonwal

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