Browse by Stream
QnA
Home
QnA
Go To Your Study Dashboard

Get Answers to all your Questions

header-bg qa

Energy released in the fission of a single \mathrm{{ }_{92} U^{235}} nucleus is \mathrm{200 \, \mathrm{MeV}}. The fission rate of a \mathrm{{ }_{92} U^{235}} fuelled reactor operating at a power level of \mathrm{5 \mathrm{~W}} is

Option: 1

1.56 \times 10^{+10} \mathrm{~s}^{-1}


Option: 2

1.56 \times 10^{+11} \mathrm{~s}^{-1}


Option: 3

1.56 \times 10^{+16} \mathrm{~s}^{-1}


Option: 4

1.56 \times 10^{+17} s^{-1}


Answers (1)

best_answer

\mathrm{\frac{\text { Energy }}{\text { Fission }}=200\, \mathrm{MeV}=200 \times 10^6 \times 1.6 \times 10^{-19} \mathrm{~J}}

\mathrm{\text { Fission rate }=\frac{5}{200 \: \mathrm{MeV}}=1.56 \times 10^{11} \text { fission}/\mathrm{sec}}.

Posted by

manish painkra

View full answer

JEE Main high-scoring chapters and topics

Study 40% syllabus and score up to 100% marks in JEE

Similar Questions

Trending Articles/News

anam-khan

JEE Main 2024: NTA debars 39 candidates for 3 years on account of using unfair means
anam-khan

JEE Main 2024 session 2 paper 2 answer key objection window closes today; fees
anam-khan

JEE Main 2024 Topper: Farmer’s son Gajare Nilkrishna says ‘keep questioning until you understand’

Latest Question