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Find the reading of the ammeters A_{1}  (in ampere) connected as shown in the network. 

Option: 1

1A


Option: 2

2A


Option: 3

5A


Option: 4

6A


Answers (1)

best_answer

Here all the resistance will be in parallel.

Current through 12\Omega is I_{1}=24/12=2A Hence reading of A_{1}=I_{1}=2A

 

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Sayak

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