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  •  For a given transistor amplifier circuit in configuration <img alt="\mathrm{V}_{\mathrm{CC}}=

 For a given transistor amplifier circuit in \mathrm{CE} configuration \mathrm{V}_{\mathrm{CC}}=1 \mathrm{~V}, \mathrm{R}_{\mathrm{C}}=1 \mathrm{k} \Omega, \mathrm{R}_{\mathrm{b}}=100 \mathrm{k} \Omega$ and $\beta=100.Value of base current \mathrm{I}_{\mathrm{b}} is

Option: 1

I_{b}=100 \mu \mathrm{A}


Option: 2

\mathrm{I}_{\mathrm{b}}=10 \mu \mathrm{A}


Option: 3

\mathrm{I}_{b}=0.1 \mu \mathrm{A}


Option: 4

\mathrm{I}_{\mathrm{b}}=1.0 \mu \mathrm{A}


Answers (1)

best_answer

\mathrm{V}_{\mathrm{cc}}=1 \mathrm{~V}

\mathrm{R}_{\mathrm{c}} \mathrm{I}_{\mathrm{c}}=1
\mathrm{I}_{\mathrm{c}}=\frac{1}{10^{3}} \mathrm{~A}=1 \mathrm{~mA}
\beta=\frac{\mathrm{I}_{\mathrm{c}}}{\mathrm{I}_{\beta}} \\
\mathrm{I}_{\beta}=\frac{\mathrm{I}_{\mathrm{C}}}{\beta}
=1 \times 10^{-5} \mathrm{~A}

=10 \mu \mathrm{A}

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