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For a transistor, the current amplification factor is 0.8. The transistor is connected in common emitter configuration. The change in the collector current when the base current changes by 6 mA is

Option: 1

6 mA


Option: 2

4.8 mA


Option: 3

24 mA


Option: 4

8 mA


Answers (1)

best_answer

Given that,

\mathrm{\begin{aligned} & \beta=0.8 \\ & \Delta \mathrm{l}_{\mathrm{b}}=6 \mathrm{~mA} \\ & \because \Delta \mathrm{l}_{\mathrm{c}}=\beta \Delta \mathrm{l}_{\mathrm{b}} \\ & \therefore \Delta \mathrm{l}_{\mathrm{c}}=0.8 \times 6 \mathrm{~mA}=4.8 \mathrm{~mA} \end{aligned}}

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