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  • Give answer! - A particle is moving with a velocitywhere K is a constant. The general equation for its path is: - Kinematics - JEE Main

 

A particle is moving with a velocity \vec{\upsilon }=K(y\hat{i}+x\hat{j}), where K is a constant. The general equation for its path is:

  • Option 1)

     y=x^{2}+constant

      

  • Option 2)

    y^{2}=x+constant

  • Option 3)

    y^{2}=x^{2}+constant

  • Option 4)

    xy = constant

Answers (1)

best_answer

 

Equation of path of a projectile -

y= x \tan \theta\: - \: \frac{gx^{2}}{2u^{2}\cos ^{2}\theta }

it is equation of parabola

g\rightarrow    Acceleratio due to gravity

u\rightarrow    initial velocity

\theta = Angle of projection

- wherein

Path followed by a projectile is parabolic is nature.

V = k (yi + xj)

\frac{dx}{dt} = ky

\frac{dy}{dt} = kx

\frac{dy}{dx} = \frac{x}{y}

\Rightarrow xdx = ydy , on integrating this

y2 = x2 + C

 

 


Option 1)

 y=x^{2}+constant

  

Option 2)

y^{2}=x+constant

Option 3)

y^{2}=x^{2}+constant

Option 4)

xy = constant

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