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The major product of the following reaction is :

  • Option 1)

     

  • Option 2)

    CH_{3}CH_{2}C\equiv CH

     

  • Option 3)

    CH_{3}CH=CHCH_{2}NH_{2}

  • Option 4)

    CH_{3}CH=C=CH_{2}

Answers (1)

best_answer

 

From alkyl halide -

Alkyl halides on heating with alcoholic potash eliminate one molecule of Hydrogen acid to form alkene.

- wherein

 

 

Preparation of alkyne from calcium carbide -

Ethyne is prepared by treating calcium carbide with water.

- wherein

CaC_{2}+2H_{2}O\rightarrow C_{2}H_{2}+Ca(OH)_{2}

 

 

Preparation of alkene from alkyne -

Alkynes on partial reduction with calculated amount of H2 in presence of Pd with charcool give alkenes.

- wherein

As we have learned

\xrightarrow[liq\: NH_{3}]{NaNH_{2}}CH_{3}-CH_{2}-C\equiv CH

 

 

 


Option 1)

 

Option 2)

CH_{3}CH_{2}C\equiv CH

 

Option 3)

CH_{3}CH=CHCH_{2}NH_{2}

Option 4)

CH_{3}CH=C=CH_{2}

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