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The major product of the following reaction is :
Option: 1

Option: 2

Option: 3
Option: 4 

 

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Posted by

vishal kumar

The decreasing order of reactivity towards dehydrohalogenation (E_{1}) reaction of the following compounds is: 
Option: 1 B>A>D>C
Option: 2 B>D>C>A
Option: 3 B>D>A>C
Option: 4 D>B>C>A
 

Mechanism

 


E1 reaction proceeds via carbocation formation, therefore greater the stability of carbocation, faster the E1 reaction.

Therefore, Option(4) is correct.

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Posted by

Kuldeep Maurya

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 Consider the following reactions:        (a) \mathrm{(CH_{3})_{3}CCH(OH)CH_{3}\: \overset{conc.\: H_{2}SO_{4}}{\longrightarrow}}        (b) \mathrm{(CH_{3})_{2}CHCH(Br)CH_{3}\: \overset{alc.\: KOH}{\longrightarrow}}        (c) \mathrm{(CH_{3})_{2}CHCH(Br)CH_{3}\: \overset{(CH_{3})_{3}O^{-}K^{+}}{\longrightarrow}}        (d) \mathrm{(CH_{3})_{2}COHCH_{2}CHO\: \overset{\Delta }{\longrightarrow}} Which of these reaction(s) will not produce Saytzeff product?
Option: 1 (c) only
Option: 2 (b) and (d)
Option: 3(a), (c) and (d)
Option: 4 (d) only
 

The reactions occur as follows:

 

Therefore, Option(1) is correct.

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Posted by

Kuldeep Maurya

1-methyl ethylene oxide when treated with an excess of HBr produces:
Option: 1
Option: 2
Option: 3
Option: 4
 

The given reaction occurs as

Therefore, Option(3) is correct.

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Kuldeep Maurya

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In the following sequence of reactions the maximum number of atoms present in molecule 'C' in one plane is _____. A\xrightarrow[Cu \; tu\; be]{Red\; hot}B\xrightarrow[Anhydrous\; AlCl_{3}]{CH_{3}Cl(I.eq.)}C (A is a lowest molecular weight alkyne )
 

 

 

Number of atoms in one plane = 13.

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Posted by

Kuldeep Maurya

The major product in the following reaction is :
Option: 1
Option: 2
Option: 3
Option: 4

 

In the given reaction, there is the formation of an aromatic species upon protonation of the carbonyl group and subsequent polarisation.

Therefore, Option(3) is correct.

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Posted by

Kuldeep Maurya

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The major product \left [ B \right ] in the following sequence of reaction is : CH_{3}-\underset{CH(CH_{3})_{2}}{C}=CH-CH_{2}CH_{3}\xrightarrow[(i)H_{2}SO_{2},OH^{\ominus })]{(i)B_{2}H_{6}}\left [ A \right ]\xrightarrow[\Delta ]{dil.H_{2}SO_{4}}\left [ B \right ]
Option: 1    
Option: 2    
Option: 3    
Option: 4
 
 

 

 

Therefore, Option(3) is correct.

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Kuldeep Maurya

For the following Assertion and Reason, the correct option is : Assertion: For hydrogenation reactions, the catalytic activity increases from Group 5 to Group 11 metals with maximum activity shown by Group 7-9 elements. Reason: The reactants are most strongly adsorbed on group 7-9 elements.
Option: 1 The assertion is true, but the reason is false.  

Option: 2 Both assertion and reason are true but the reason is not the correct explanation for the assertion.  
 
Option: 3 Both assertion and reason are true but the reason is the correct explanation for the assertion.

Option: 4 Both assertion and reason are false.
 

The metals of groups 7, 8 and 9 do not form hydride. Even from group 6, only chromium forms CrH. These hydrides conduct heat and electricity though not as efficiently as their parent metals do.

"For hydrogenation reactions, the catalytic activity increases from Group 5 to Group 11 metals with maximum activity shown by Group 7-9 elements." This statement is wrong as the metals of groups 7, 8 and 9 do not form hydride.

Both assertion and reason are false.

Therefore, Option(4) is correct.

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Posted by

vishal kumar

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An unsaturated hydrocarbon X absorbs two hydrogen molecules on catalytic hydrogenation, and also gives following reaction: \mathrm{X\xrightarrow[H_{2}O_2]{O_{3}} A\ {(3-oxohexanedioic\ acid)}} The compound X is correctly represented in
Option: 1

Option: 2

Option: 3 

Option: 4 
 

The reaction occurs as:

Therefore, Option(2) is correct.

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Posted by

vishal kumar

The major products of the following reaction are :  
Option: 1
Option: 2
Option: 3
Option: 4
 

The reaction occurs as follows:

Therefore, Option(3) is correct.

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Posted by

Kuldeep Maurya

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