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Given below are the statements about diborane (a) Diborane is prepared by the oxidation of \mathrm{NaBH}_{4}$ with $\mathrm{I}_{2} (b) Each boron atom is in \mathrm{sp}^{2} hybridized state (c) Diborane has one bridged 3 centre-2-electron bond (d) Diborane is a planar molecule The option with correct statement(s) is -
Option: 1 (c) and (d) only
Option: 2 (a) only
Option: 3 (c) only
Option: 4 (a) and (b) only

Answers (1)

best_answer

As we have learnt,

Diborane can be prepared by the reaction of \text{NaBH}_{4} with \text{I}_{2}

\mathrm{I_{2}+\text { NaBH}_{4} \longrightarrow \mathrm{B}_{2} \mathrm{H}_{6}+\mathrm{NaI}+\mathrm{H}_{2}}

The structure of diborane is given as

It has \text{sp}^{3} hybridised Boron atoms. It is non planar and has an tetrahedral arrangement of atoms. It contains two bridged 3-centre-2-electron bonds.

Hence, the correct answer is option (2)

Posted by

sudhir.kumar

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